Question

NASA is painting the bose vone of a sounding rocket with a special sealant which reduces the air-drag on the rocket. If they need to do two coats of the sealant, how many square feet are they painting? use 3.14

Answer 1

Given data:

The given figure of the cone.

The expression for two coats of the area of the painting is,

$A=2(\pi)(r)(l)$

Substitute the given values in the above expression.

$\begin{gathered} A=2(3.14)(\frac{3\text{ ft}}{2})(6\text{ ft)} \\ =56.52ft^2 \end{gathered}$

Thus, the area for two coats of painting is 56.52 sq-feet.