The formula that relates the wattage of an appliance to the cost to run the appliance is 10000 where W is the wattage of appliance, C is the cost to use the appliance per month, t is the time in hours per month, and c is the cost of electricity per kilowatt hour. Use $0.15 per kilowatt-hour for the cost of electricity a. How much does it cost to run a 60-watt light bulb 720 hours a month? A.$0.15 C.$12.32 b. $6.48 D. $288

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30-10-2022
Mathematics

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The formula that relates the wattage of an appliance to the cost to run the appliance is 10000 where W is the wattage of appliance, C is the cost to use the appliance per month, t is the time in hours per month, and c is the cost of electricity per kilowatt hour. Use $0.15 per kilowatt-hour for the cost of electricity a. How much does it cost to run a 60-watt light bulb 720 hours a month? A.$0.15 C.$12.32 b. $6.48 D. $288

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BrynnleyJ157309 BrynnleyJ157309 · Answer 1 · 2022-10-30T02:12:21+01:00

Given the formula that relates the wattage (W) of an appliance to the running cost(C) to be:

[tex]W=\frac{1000C}{tc}[/tex]

where, t = time in hours per month

c = cost of electricity per kilowatt-hour

[tex]if\text{ c = \$}0.15,\text{ }t=720\text{ hours },\text{ W}=60\text{watts, C=?}[/tex]

Using the relation, substitute the given values above in order to find C

[tex]\begin{gathered} 60=\frac{1000C}{720\times0.15} \\ 1000C=60\times720\times0.15 \\ 1000C=6480 \\ C=\frac{6480}{1000} \\ C=6.48 \\ \\ \text{Therefore, it costs \$6.48 (option b is the best answer choice)} \end{gathered}[/tex]