Given the claim that the minority of adults would erase their personal information online if they could
[tex]\begin{gathered} \sigma=s\tan dard\text{ deviation} \\ \mu=\operatorname{mean} \\ \text{therefore population=p} \end{gathered}[/tex]the parameter to be used to represent this claim will be
[tex]p[/tex]The information shows that 43% of the adults would erase their information online
This means that based on the logic, the percentage of the minority adults should be =43% of the adult population
[tex]\begin{gathered} \text{percentage of minority=43\%=}\frac{43}{100}=0.43 \\ \text{therefore we can say that} \\ p=0.43 \end{gathered}[/tex]The word "WOULD" is a word under probability but one thing is for sure the minority adults that would erase their information online will not be more than 43%
Considering the value of selected adults by the firm which is = 483
The population of minority adults will be calculated as
[tex]\begin{gathered} \frac{43}{100}\times483=207.69 \\ so\text{ we can therefore say that } \\ p=207.69 \end{gathered}[/tex]p=0.43 (In terms of percentage)
p=207.69 (in terms of the population)