Question

A Mars rover traveled from point a to point b at a speed of 4 cm/sec. Worsening conditions during the return trip caused the rover to travel at a speed of 2.5 cm/sec, and increased travel time by 15 minutes. What is the distance between point a and point b.

Answer 1

At a speed of 4 cm/sec, the distance between point a and point b is equal to 6,000 cm or 60 m.

How to calculate the speed?

Mathematically, the speed of a physical object can be calculated by using this formula;

Speed = distance/time

Making time the subject of formula, we have:

Time = distance/speed

• Let d represent the distance travelled by Mars rover.
• Let t represent the time taken.

At a speed of 4 cm/sec, the time taken is given by:

Time = distance/speed

t = d/4

4t = d      .....equation 1.

At a speed of 2.5 cm/sec, the time taken is given by:

Note: 1 minute is equal to 60 seconds.

(t + 15 × 60) = d/2.5

t + 900 = d/2.5

Cross-multiplying, we have:

2.5(t + 900) = d

2.5t + 2250 = d    ......equation 2.

Equating equation 1 and equation 2, we have:

4t = 2.5t + 2250

4t - 2.5t = 2250

1.5t = 2250

Time, t = 2250/1.5

Time, t = 1,500 seconds

Now, we can determine the distance between point a and point b:

Distance, d = 4t

Distance, d = 4 × 1,500

Distance, d = 6,000 cm

In meters we have:

Distance, d = 6,000/100

Distance, d = 60 meters.

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