Question

Evaluate 16 S (x-4) dx 16 (vx – 4) dx = (Type an exact answer in simplified form.) 9

Answer 1

Solution:

$\int ^{16}_9(\sqrt[]{x}-4)dx=\frac{2}{3}\sqrt[]{x^3}-4x$

And if we evaluate between 16 and 9 we got:

$(\frac{2}{3}\sqrt[]{16^3^{}}-4(16))-(\frac{2}{3}\sqrt[]{9^3}-4(9))=\frac{128}{3}-64-18-36=\frac{74}{3}-28=-\frac{10}{3}$