Answer:
• (a)f'(x)=0
,• (b)f'(x)=-67
Explanation:
(a)Given the function:
[tex]f(x)=72[/tex]By the rules of differentiation given below:
[tex]\begin{gathered} \frac{d}{dx}(c)=0 \\ where\text{ c is a constant.} \end{gathered}[/tex]Therefore:
[tex]\begin{gathered} \frac{d}{dx}(72)=0 \\ f^{\prime}(x)=0 \end{gathered}[/tex](b) Given the function:
[tex]f\mleft(x\mright)=-67x[/tex]Using the rule of derivatives below:
[tex]\frac{d}{dx}[cf(x)]=c\frac{d}{dx}[f(x)],c\text{ a constant}[/tex]Applying this rule:
[tex]\begin{gathered} \frac{d}{dx}[-67x]=-67\frac{d}{dx}[x] \\ =-67(1) \\ \implies f^{\prime}(x)=-67 \end{gathered}[/tex]The derivative is -67.