Determine the height of triangular faces.
[tex]\begin{gathered} h=\sqrt[]{(15)^2+(\frac{15}{2})^2} \\ =\sqrt[]{225+56.25} \\ \approx16.77 \end{gathered}[/tex]Determine the surface area of figure.
[tex]\begin{gathered} S=2(15\cdot15+15\cdot15)+15\cdot15+4\cdot\frac{1}{2}\cdot15\cdot16.77 \\ =2(225+225)+225+503.1 \\ =1628.1 \end{gathered}[/tex]So surface area of figure is 1628.1 foot square.
Determine the volume of figure.
[tex]\begin{gathered} V=15\cdot15\cdot15+\frac{15\cdot15\cdot15}{3} \\ =3375+1125 \\ =4500 \end{gathered}[/tex]So volume of shape is 4500 foot cube.