Respuesta :

the given line is

[tex]y=-\frac{1}{2}x+4[/tex]

it has slope m equal to

[tex]m=-\frac{1}{2}[/tex]

anb y-intercept b equal to 4.

Since we need a perpendicular line, we know that this new line must have a "reciprocal inverse" slope mp for the

given m, that is

[tex]m_p=-\frac{1}{m}[/tex]

In our case,

[tex]m_p=-\frac{1}{-\frac{1}{2}}[/tex]

which is equal to,

[tex]m_p=2[/tex]

Hence, the form of our perpendicular line is

[tex]\begin{gathered} y=m_px+c \\ or \\ y=2x+c \end{gathered}[/tex]

we only need the y-intercept c. In order to find c, we must use the given point (-8,2).

By substituying this point into the last equation, we have

[tex]2=2(-8)+c[/tex]

hence,

[tex]\begin{gathered} 2=-16+c \\ c=2+16 \\ c=18 \end{gathered}[/tex]

Finally, the perpendicular line is

[tex]y=2x+18[/tex]

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