Here is a system of equations:3x - y = 17x + 4y = 10Explain how you can tell, without graphing, that there is only one solution to the system.

To solve the exercise, we can consider the following system of two linear equations with two unknown variables:
[tex]\begin{cases}Ax+By=C \\ Dx+Ey=F\end{cases}[/tex]If the pair (A,B) is not proportional to the pair (D,E), then there is only one solution. That is, there is no such number k that
[tex]\begin{gathered} D=kA \\ \text{ and} \\ E=kB \end{gathered}[/tex]In other words, we have to verify the following:
[tex]\begin{gathered} D=kA\Rightarrow\frac{D}{A}=k \\ E=kB\Rightarrow\frac{E}{B}=k \\ \text{ Then} \\ \frac{D}{A}\ne\frac{E}{B} \end{gathered}[/tex]In this case, we have:
[tex]\begin{cases}3x-y=17 \\ x+4y=10\end{cases}[/tex][tex]\begin{gathered} \frac{1}{3}\ne\frac{4}{-1} \\ 0.3\ne-4 \end{gathered}[/tex]Therefore, since the pair (3, -1) is not proportional to the pair (1,4), then there is only one solution for the given system of linear equations.