ThereforeSince 35% of the student plays a sport
Since there are 100 students in the group
Therefor there are 35 students in this group play sport
[tex]\frac{35}{100}\times100=35[/tex]In at least we will subtract who can play from 100%
So let us find the probability that 1 of the 2 students not play
[tex]undefined[/tex]