Question

On a beautiful spring day, Juan is playing a round of golf. He hits the golf ball with an initial velocity of 32.9 m/s at an angle of 23.7°. If it hits the ground 6.1s later, how far does it travel? Ignore air resistance.

Answer 1

Firstly, let us draw the situation:

For us to find out how far it travels, we can write the equation for displacement on the x axis. Note, however, that the velocity we'll use is the x velocity only. This gives us:

$S_x=v_xt\Rightarrow S_x=32.9*cos(23.7°)*6.1=183.76m$

Then, the distance it traveled in x is x=183.76m