Answer: 1/15
Given data
2 cans of tomato soup
3 can s of chicken soup
2 cans of cheese soup
2 cans of potato soup
1 can of beef soup
Firstly, we need to calculate the total number of cans of soup
Total number of cans of soup = 2 + 3 + 2+ 2+ 1
Total number of cans of soup = 10
Probability of chosen a can of schicken soup = 3/ 10
The total number left will be 9 because it is without replacement
Probability of chosen a can of potato soup in the next day = 2/ 9
AND means multiplication
Probability of chosen chicken and potato can of soup =
[tex]\begin{gathered} \frac{3}{10}\text{ x }\frac{2}{9} \\ =\text{ }\frac{6}{90} \\ =\text{ }\frac{1}{15} \end{gathered}[/tex]
Probability of chosen a can of chicken and potato soup is 1/15
What I mean by without replacement is that if you choose a can of chicken soup today out of the total 10 cans of soup,it will remain 9 because after consuming the soup you won't replace the empty can.
