Respuesta :
ANSWER
0.2644
EXPLANATION
The tuition costs is a random variable X normally distributed with a mean of $23600 and a standard deviation of $6023.
We have to find the probability that a randomly selected college has an annual cost between $25000 and $30000. This is,
[tex]P(25000\lt X\lt30000)[/tex]Using the standard normal distribution formula,
[tex]Z=\frac{X-\mu}{\sigma}[/tex]We have,
[tex]P(25000\lt X\lt30000)=P\left(\frac{25000-23600}{6023}\lt\frac{X-\mu}{\sigma}\lt\frac{30000-23600}{6023}\right)=P(0.23\lt Z\lt1.06)[/tex]Now, we have to look up these z-values in a z-score table. These tables show the area under the standard normal curve to the left of each z-score - i.e. they show the probability that Z is less than that value. So, to find this probability we have to separate each interval and use a complement,
So we have,
[tex]P(0.23\lt Z\lt1.06)=P(Z\lt1.06)-P(Z\lt0.23)[/tex]These z-scores in a z-table are,
So the probability is,
[tex]P(25000\lt X\lt30000)=P(Z\lt1.06)-P(Z\lt0.23)=0.8554-0.5910=0.2644[/tex]Hence, the probability that a randomly selected college will have an annual cost between $25000 and $30000 is 0.2644.


