We define the following variables and functions:
• t = time,
,• T(t) = temperature as a function of time.
From the statement, we know that:
• the initial temperature is T(0) = 100°C,
,• the temperature at time t = 5 minutes is T(5) = 70°C.
If we consider a linear model to describe this problem, we have the general linear equation:
[tex]T(t)=m\cdot t+T(0)\text{.}[/tex]Where m is the rate of change of the temperature. Replacing the data above for t = 5 min, we have:
[tex]T(5)=m\cdot5\min +100\degree C=70\degree C.[/tex]Solving for m, we get:
[tex]\begin{gathered} m\cdot5\min =70\degree C-100\degree C, \\ m\cdot5\min =-30\degree C, \\ m=\frac{-30\degree C}{5\min}=-6\cdot\frac{\degree C}{\min}\text{.} \end{gathered}[/tex]Replacing this value and T(0) = 100°C in the general equation, we get:
[tex]T(t)=-6\cdot\frac{\degree C}{\min}\cdot t+100\degree C\text{.}[/tex]Answer
The equation that model this problem is:
[tex]T(t)=-6\cdot\frac{\degree C}{\min}\cdot t+100\degree C\text{.}[/tex]