Respuesta :

SOLUTION

Write out the expression given

[tex](\sqrt[5]{x^7)}^3[/tex]

The fifth root of a number is 1/5 of the number at the exponent

Hence

[tex](x^7)^{\frac{1}{5}}=x^{\frac{7}{5}}[/tex]

Then, take the cube of the last exponent

[tex]\begin{gathered} (x^{\frac{7}{5}})^3 \\ \end{gathered}[/tex]

Using the product power rule we take the product of the exponent

[tex]\begin{gathered} ^{}(x^a)^b=x^{ab} \\ \text{Then } \\ (x^{\frac{7}{5}})^3=x^{\frac{7}{5}\times3}=x^{\frac{21}{5}} \end{gathered}[/tex]

Hence

The rational exponent of the given expression is

[tex]x^{\frac{21}{5}}[/tex]

The rational exponent of the given expression is x^21/5

Note; 21/5 is the exponent

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