We have the following:
[tex]x+1>-5\cdot(7-2x)[/tex]solving for x:
[tex]\begin{gathered} x+1>-5\cdot(7-2x) \\ x+1-1>-35+10x-1 \\ x>10x-36 \\ x-10x>10x-10x-36 \\ -9x>-36 \\ 9x<36 \\ x<\frac{36}{9} \\ x<4 \end{gathered}[/tex]The answer is:
[tex]\begin{gathered} x<4 \\ (-\infty,4) \end{gathered}[/tex]
