Question

if tan theta = 8/6, 0 less than = to theta less than = to pi/2 what is sin (theta)= cos(theta)=cos (theta)=?$if \: \tan(theta) = \frac{8}{6} \: 0 \leqslant theta \leqslant \frac{\pi}{2 \: then \: what \: is \: \sin(thta =) \\ \cos(theta \: csc \: theta)$

Answer 1

$\begin{gathered} \tan \theta=\frac{8}{6} \\ \\ 0\leq\theta\leq\frac{\pi}{2} \\ \\ \end{gathered}$

Use the next identities:

$\begin{gathered} \tan \theta=\frac{\sin \theta}{\cos \theta} \\ \\ \csc \theta=\frac{1}{\sin \theta} \end{gathered}$

Then, you get that:

$\begin{gathered} \sin \theta=8 \\ \cos \theta=6 \\ \csc \theta=\frac{1}{8} \end{gathered}$