Find the direction angle of the vector below. Round to the nearest thousandth. Show all work.

For a vector given in the form:
[tex]v=ai+bj[/tex]the direction angle of the vector is given to be:
[tex]\theta=\tan ^{-1}(\frac{b}{a})[/tex]The vector is given in the question to be:
[tex]v=3i+4j[/tex]Therefore, we have that:
[tex]\begin{gathered} a=3 \\ b=4 \end{gathered}[/tex]Hence, the direction angle is calculated to be:
[tex]\begin{gathered} \theta=\tan ^{-1}(\frac{4}{3}) \\ \theta=53.130\degree \end{gathered}[/tex]The direction angle is 53.130° to the nearest thousandth.