Given the expression:
sin80°
Let's rewrite the given expression in terms of apropriate cofunction.
To rewrite, apply the formula:
[tex]\sin x=\cos (90-x)[/tex]Hence, we have:
[tex]\begin{gathered} \sin 80=\cos (90-80) \\ \\ \sin 80=\cos 10^o \end{gathered}[/tex]Therefore, sin80° in terms of the appropraite cofunction is cos(10)°.
ANSWER:
cos10°
