ANSWER:
[tex](x+2)\cdot(x-4)[/tex]STEP-BY-STEP EXPLANATION:
We have the following equation
[tex]x^2-2x-8=0[/tex]We factor by decomposing as follows:
[tex]\begin{gathered} -2x=2x-4x \\ \text{replacing} \\ x^2+2x-4x-8 \\ (x^2+2x)+(-4x-8) \\ x(x+2)-4(x+2) \\ (x+2)\cdot(x-4) \end{gathered}[/tex]
