Variables
• x: Number of phone calls the first evening
,• y: Number of phone calls the second evening
,• z: Number of phone calls the third evening
Given that Karen received a total of 158 phone calls, then:
[tex]x+y+z=158\text{ (eq. 1)}[/tex]Given that in the first evening, she received 8 more calls than the second evening, then:
[tex]x=8+y\text{ (eq. 2)}[/tex]Given that in the third evening, she received 4 times as many calls as the second evening, then:
[tex]z=4y\text{ (eq. 3)}[/tex]Substituting equations 2 and 3 into equation 1 and solving for y:
[tex]\begin{gathered} (8+y)+y+4y=158 \\ 8+(y+y+4y)=158 \\ 8+6y=158 \\ 8+6y-8=158-8 \\ 6y=150 \\ \frac{6y}{6}=\frac{150}{6} \\ y=25 \end{gathered}[/tex]Substituting y = 25 into equations 2 and 3:
[tex]\begin{gathered} x=8+25=33 \\ z=4\cdot25=100 \end{gathered}[/tex]The final answer is:
• Number of phone calls the first evening:, 33
,• Number of phone calls the second evening: ,25
,• Number of phone calls the third evening: ,100