Question

A soup can has a 3 7/8 diameter and is 4" tall. what the is the area of the paper that will be used to make the label of the can if the proper covers the entire lateral surface area? Use 3.14159 for π.

Answer 1

Answer:

$A_l=263.89356in^2$

Explanation: We need to find the lateral-Area of the can, which means we must exclude the area of the base (top-bottom).

$\begin{gathered} D=3\frac{7}{8}in \\ h=4in \\ \pi=3.14159 \end{gathered}$

The lateral-Area is as follows:

$\begin{gathered} A_l=h\times C \\ \text{ Where C is circumference of the can:} \\ \therefore\rightarrow \\ A_l=(h\times C)=h\times(\pi\times D)=(4in)\times(3.14159\times3\frac{7}{8})\text{ in} \\ A_l=(4\times3.14159\times3\frac{7}{8})in^2=(4\times3.14159\times\frac{168}{8})in^2 \\ A_l=263.89356in^2 \end{gathered}$