Given the equation of a Conic Section:
[tex]x^2-4xy+3x+25y-6=0[/tex]You need to remember that the General Form for a Conic Section is:
[tex]Ax^2+Bxy+Cy^2+Dx+Ey+F=0[/tex]By definition, you can use this formula to find the Discriminant, in order to determine the shape of the Conic Section:
[tex]Discriminant=B^2-4AC[/tex]If:
- The Discriminant is negative, then the Conic Section is an Ellipse.
- The Discriminant is greater than zero, then the Conic Section is a Hyperbola.
- The Discriminant is zero, then the Conic Section is a Parabola.
In this case, you can identify that:
[tex]\begin{gathered} A=1 \\ B=-4 \\ C=0 \end{gathered}[/tex]Therefore, by substituting values into the formula and evaluating, you get:
[tex]Discriminant=(-4)^2-4(1)(0)C[/tex][tex]Discriminant=16[/tex]Notice that the discriminant is greater than zero. Therefore the Conic Section is a Hyperbola.
Hence, the answer is: It represents a Hyperbola because the Discriminant is greater than zero.