Given function:
[tex]f(x)\text{ = -3x}^2\text{ + 18x - 21}[/tex]
Given the general form of a quadratic equation:
[tex]f(x)\text{ = ax}^2\text{ + bx + c}[/tex]
The vertex form of the quadratic equation is:
[tex]\begin{gathered} f(x)\text{ = a\lparen x- h\rparen}^2\text{ + k} \\ Where\text{ h = -}\frac{b}{2a} \\ k\text{ = f\lparen h\rparen} \end{gathered}[/tex]
Let us proceed to find the vertex of the quadratic equation:
We have
a = -3, b = 18, c = -21
The x-coordinate of the vertex:
[tex]\begin{gathered} h\text{ = - }\frac{18}{2\times-3} \\ =\text{ 3} \end{gathered}[/tex]
The y-coordinate of the vertex:
[tex]\begin{gathered} k\text{ = -3\lparen3\rparen}^2\text{ + 18\lparen3\rparen -21} \\ =\text{ 6} \end{gathered}[/tex]
Hence, the vertex of the equation is at (3, 6)
The equation in vertex form is thus:
[tex]f(x)\text{ = -3\lparen x-3\rparen}^2\text{ + 6}[/tex]
Answer:
The statements that are correct are:
Option A and option E