Answer:
136 m
Explanation:
The diagram illustrating this problem is attached below:
Using trigonometric ratio:
[tex]\tan 32\degree=\frac{85}{x}[/tex]We solve for x, the distance between the hiker and the cliff's base.
[tex]\begin{gathered} x\tan 32\degree=85 \\ \frac{x\tan 32\degree}{\tan 32\degree}=\frac{85}{\tan 32\degree} \\ x=136.03m \\ x\approx136m \end{gathered}[/tex]To the nearest meter, the distance between the hiker and the cliff's base is 136m.