Question

The probability distribution of a game is shown in the table. Find the expected number of points won per play. Round to the nearest tenth if needed.0 2 5 101/6. 1/6. 1/2. 1/6a5.7b4.7c4.5d5

Answer 1

Solution

$\begin{gathered} Expected\text{ }Value=0(\frac{1}{6})+2(\frac{1}{6})+5(\frac{1}{2})+10(\frac{1}{6}) \\ \\ Expected\text{ }Value=\frac{2}{6}+\frac{15}{6}+\frac{10}{6} \\ \\ Expected\text{ }Value=\frac{27}{6} \\ \\ Expected\text{ }Value=\frac{9}{2} \\ \\ Expected\text{ }Value=4.5 \end{gathered}$

Correct Option C