Draw a closed circle on -6 and shade to the left.Draw an open circle on -6 and shade to the right.Draw an open circle on -6 and shade to the left.Draw a closed circle on -6 and shade to the right.

Given:
An inequality is
[tex]\frac{x}{3}\leq-2[/tex]Required:
Draw the graph of the inequality.
Explanation:
The given inequality is
[tex]\frac{x}{3}\leqslant-2[/tex]Multiply both sides by 3.
[tex]\begin{gathered} \frac{x}{3}\times3\leqslant-2\times3 \\ x\leq-6 \end{gathered}[/tex]The graph of the inequality is
Thus the solution region to the inequality is the closed point at x = -6 and the region to the left side because the inequality consists of the equal and the less significant.
Final Answer:
The first option is the correct answer.