Draw a closed circle on -6 and shade to the left.Draw an open circle on -6 and shade to the right.Draw an open circle on -6 and shade to the left.Draw a closed circle on -6 and shade to the right.

Draw a closed circle on 6 and shade to the leftDraw an open circle on 6 and shade to the rightDraw an open circle on 6 and shade to the leftDraw a closed circle class=

Respuesta :

Given:

An inequality is

[tex]\frac{x}{3}\leq-2[/tex]

Required:

Draw the graph of the inequality.

Explanation:

The given inequality is

[tex]\frac{x}{3}\leqslant-2[/tex]

Multiply both sides by 3.

[tex]\begin{gathered} \frac{x}{3}\times3\leqslant-2\times3 \\ x\leq-6 \end{gathered}[/tex]

The graph of the inequality is

Thus the solution region to the inequality is the closed point at x = -6 and the region to the left side because the inequality consists of the equal and the less significant.

Final Answer:

The first option is the correct answer.

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