Answer:
Choice D. 2 solutions
Explanation:
Adding the two equations gives
[tex]\begin{gathered} x^2+y^2=25 \\ x-y^2=-5 \\ --------- \\ x^2+x=20 \end{gathered}[/tex]
Therefore, we have the quadratic equations
[tex]x^2+x-20=0[/tex]
which has the solutions ( using quadratic formula)
[tex]x=\frac{-1\pm\sqrt[]{1^2-4(1)(-20)}}{2}[/tex][tex]x=\frac{-1\pm\sqrt[]{81}}{2}[/tex]
meaning we have two values of x that satisfy the system of equations.
Therefore, choice D is the correct answer.
