Use the given special right triangle to find the value of sin 6 2x TV 3 TT 3 х

hello
to solve this question, we need to use trigonometric ratio
using trigonometric ratio
SOHCAHTOA
[tex]\begin{gathered} \text{SOHCAHTOA} \\ \text{SOH}=\sin \theta=\frac{opp}{adj} \\ \text{CAH}=\text{cos}\theta=\frac{adj}{hyp} \\ \text{TOA}=\text{tan}\theta=\frac{opp}{adj} \end{gathered}[/tex]from the given angle, we can find the value of what is required of us
[tex]\begin{gathered} \sin \frac{\pi}{3}=\frac{opp}{adj} \\ \sin \frac{\pi}{3}=\frac{\sqrt[x]{3}}{x} \\ \sin \frac{\pi}{3}=\sqrt[]{3} \end{gathered}[/tex]