Given are two congurent traingles, in which the angles of the traingle are,
[tex]\begin{gathered} 69^{\circ};50^{\circ};(2x+5) \\ \end{gathered}[/tex]
sum of the angles in the traingle is always 180.
thus,
[tex]\begin{gathered} 69+50+2x+5=180 \\ 124+2x=180 \\ 2x=180-124 \\ 2x=56 \\ x=\frac{56}{2} \\ x=28 \end{gathered}[/tex]
therefore, x=28
