SOLUTION
Step1: Write out the formula for test statistic
[tex]t=\frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt[]{n}}}[/tex]
Step2: Identify the given parameter in the question
[tex]\begin{gathered} \mu=58.9 \\ \bar{x}=60.5 \\ n=18 \\ \sigma=13.4 \\ \text{where } \\ n=\text{sample size,}\bar{x}=\text{sample mean }\sigma=s\tan dard\text{ deviation } \end{gathered}[/tex]
Step3; Substitute the values into the formula
[tex]\begin{gathered} t=\frac{60.5-58.9}{\frac{13.4}{\sqrt[]{18}}} \\ \\ t=\frac{1.6}{\frac{13.4}{4.24}} \\ \\ t=\frac{1.6}{3.16} \end{gathered}[/tex]
Step4: Simplify the expression in the last line above
[tex]\begin{gathered} t=\frac{1.6}{3.16} \\ \\ t=0.506 \end{gathered}[/tex]
Therefore the test statistics is 0.506 to 3 d.p
