Given:
The initial velocity of the car, u=0 m/s
The acceleration of the car, a=3.34 m/s²
The time interval, t=12.1 s
To find:
The distance covered by the car.
Explanation:
From the equation of motion,
[tex]d=ut+\frac{1}{2}at^2[/tex]On substituting the known values,
[tex]\begin{gathered} d=0+\frac{1}{2}\times3.34\times12.1^2 \\ =244.5\text{ m} \end{gathered}[/tex]Final answer:
The distance covered by the car is 244.5 m
