Question

Determine if the given values are solutions of the equation.

Answer 1

Given the equation:

$x^2-16=0$

Given the solutions:

• x = -2

,

• x = 2

,

• x = 4

Let's determine the correct values of the solution.

Let's solve the equation for x.

Add 16 to both sides:

$\begin{gathered} x^2-16+16=0+16 \\ \\ x^2=16 \end{gathered}$

Take the square root of both sides:

$\begin{gathered} \sqrt[]{x^2}=\pm\sqrt[]{16} \\ \\ x=\pm4 \\ \\ x=-4,\text{ 4} \end{gathered}$

Therefore, the solutions of the equation are:

x = -4, x = 4

Therefore, we have:

• x = -2

No, it is not a solution

• x = 2

No, it is not a solution.

• x = 4

Yes, it is a solution.