Given the equation:
[tex]x^2-16=0[/tex]
Given the solutions:
• x = -2
,
• x = 2
,
• x = 4
Let's determine the correct values of the solution.
Let's solve the equation for x.
Add 16 to both sides:
[tex]\begin{gathered} x^2-16+16=0+16 \\ \\ x^2=16 \end{gathered}[/tex]
Take the square root of both sides:
[tex]\begin{gathered} \sqrt[]{x^2}=\pm\sqrt[]{16} \\ \\ x=\pm4 \\ \\ x=-4,\text{ 4} \end{gathered}[/tex]
Therefore, the solutions of the equation are:
x = -4, x = 4
Therefore, we have:
• x = -2
No, it is not a solution
• x = 2
No, it is not a solution.
• x = 4
Yes, it is a solution.
