[tex]\begin{gathered} \text{Given} \\ -3x+8y=4 \\ 3x-2y=8 \end{gathered}[/tex]
Add each terms from both equations
-3x + 8y = 4
+ (3x - 2y = 8)
0x + 6y = 12
6y = 12
Solve for y, using 6y = 12
[tex]\begin{gathered} 6y=12 \\ \frac{6y}{6}=\frac{12}{6} \\ y=2 \end{gathered}[/tex]
Substitute y = 2, to any of the two equation, in this case, we will use the second equation (using the first equation will yield the same result)
[tex]\begin{gathered} \text{If }y=2,\text{ THEN} \\ 3x-2y=8\text{ \lparen second equation\rparen} \\ 3x-2(2)=8 \\ 3x-4=8 \\ 3x=8+4 \\ 3x=12 \\ \frac{3x}{3}=\frac{12}{3} \\ x=4 \end{gathered}[/tex]
With x = 4, and y =2, the solution in ordered pair form is (4,2).
