Question

If 32.15 mL of a 0.1126 M HCl(aq) solution is used to titrate 14.78 mL of aNa2CO3(aq) solution, what is the molarity of the sodium carbonatesolution according to this equation: 2HCL+Na2CO3—->CO2+H2O+2NaCl

Answer 1

The reaction here is:

2HCL + Na2CO3 => CO2+ H2O+ 2NaCl (it is used for another way to solve the exercise)

To find the molarity of Na2CO3, we will use the next equation:

M1 x V1 = M2 x V2 (1)

1 is for HCl

2 is for Na2CO3

M for molarity and V for volume

Procedure:

We need to clear M2 from (1):

M1 x V1/V2 = M2

0.1126 M x 32.15 mL/14.78 mL = 0.2449 M = M2

Answer: M2 = 0.2449 M