Question

y=-16x^2+248x+116 round to the nearest 100th of second

Answer 1

We have the expression:

$y=16x^2+248x+116$

We now, solve using the quadratic function:

$x=\frac{-(248)\pm\sqrt[]{(248)^2-4(16)(116)}}{2(16)}$

Now, we will have that x has the following values:

$x\approx-0.48$

and:

$x\approx-15.02$