The given expression is,
[tex]\frac{1}{2}(w-6)+\frac{1}{4}(w+12)[/tex]Solving we have,
[tex]\begin{gathered} \frac{w}{2}-\frac{6}{2}+\frac{w}{4}+\frac{12}{4}=\frac{4w+2w}{8}+0 \\ \text{ =}\frac{6w}{8}=\frac{3}{4}w \end{gathered}[/tex]Thus, the answer is (3/4)w