Question

Ramona has $18 that she can spend on food for her dog dry dog food cause 5.50 per small bag and wet dog food cost $3 per can enter a linear inequality that describes how many bags and cans of dog food Ramona can buy let X represent the number of bags of dry dog food let y represent the number of cans of wet dog food and treat the confession as a fraction in simplest form

Answer 1

let x represent the number of bags of dry dog food

let y represent the number of cans of wet dog food

We were told that one bag of dry dog good costs $5.5. This means that the cost of x bags of dry dog food is 5.5x. Also, we were told that one can of wet dog good costs $3. This means that the cost of y cans of wet dog food is 3y

Given that she has onle $18 to spend, it means that the amount that she can spend must be lesser than or equal to $18. The inequality representing this scenario would be

$\begin{gathered} 5.5x\text{ + 3y }\leq\text{ 18} \\ \text{expressing as fraction, it becomes} \\ \frac{11x}{2}\text{ + 3y }\leq\text{ 18} \end{gathered}$