Given:
The resistance of the resistors, R₁=4 Ω
And R₂=3 Ω
And R₃=5 Ω
The current in the circuit is I=0.1 A
To find:
The potential difference in the circuit.
Explanation:
All the resistors are connected in series with the battery. The equivalent resistance of the resistors connected in the series is given by,
[tex]R=R_1+R_2+R_3[/tex]
On substituting the known values,
[tex]\begin{gathered} R=4+3+5 \\ =12\text{ }\Omega \end{gathered}[/tex]
From Ohm's law, the potential difference of the circuit is directly proportional to the current in the circuit.
Thus,
[tex]V=IR[/tex]
On substituting the known values,
[tex]\begin{gathered} V=0.1\times12 \\ =1.2\text{ V} \end{gathered}[/tex]
Final answer:
The potential
