Question

the temperature of a sample of water increases from 15.0c to 30c as it absorbs 5000j of heat what is the mass of the sample? specific heat of water is 2.03 j/gc

Answer 1

The formula that relates the heat and the temperature change is:

$Q=mc\Delta T$

Where Q is the heat, m is the mass, c is the specific heat and ΔT is the temperature change.

Since it absorbes heat, the sign of Q is positive, so:

$Q=5000j$

And the change in temperature is:

$\Delta T=T_f-T_i=30\degree C-15.0\degree C=15\degree C$

So, solving the equation for m and substituting the values, we have:

$\begin{gathered} Q=mc\Delta T \\ mc\Delta T=Q \\ m=\frac{Q}{c\Delta T}=\frac{5000j}{2.03j/g\degree C\cdot15\degree C}=164.20\ldots.g\approx164g \end{gathered}$

So, the mass of the sample is approximately 164 g.