Question

Determine the time constant of an LR circuit built using a 12.00 V battery, a 62.00 mH inductor and a 25.00 ohms resistor.

Answer 1

The time constant for an RL circuit is given by:

$\tau=\frac{L}{R}$

In this case the inductance is 62 mH and the resistance is 25 Ohms, then we have:

$\begin{gathered} \tau=\frac{62\times10^{-3}}{25} \\ \tau=2.48\times10^{-3} \end{gathered}$

Therefoe, the atime constant is 0.00248 seconds