Question

We will be changing one variable at a time to see how it affects the value of the forces. Set the variables listed in the table and document the force and determine if the charges are attracted to each other or repelled.

Answer 1

Answer:

Explanation:

The coulombs law is expressed as

F = kq1q2/r^2

where

F is the force

k is the coulomb constant and its value is 9 x 10^9 N/m^2C^2

q1 and q2 are the magnitude of the charges

r is the distance between them

From the information given,

r = 4 cm = 4/100 = 0.04m

For trial 1,

q1 = - 2μC

q2 = 8μC

Recall,

1 μC = 1 x 10^- 9 C

q1 = - 2 x 1 x 10^- 9 C

q2 = 8 x 1 x 10^- 9 C

F = (9 x 10^9 x 2 x 1 x 10^- 9 x 8 x 1 x 10^- 9)/0.04^2

F = 9 x 10^-5 N

There is an attraction

For trial 2,

q1 = - 4μC

q2 = 8μC

q1 = - 4 x 1 x 10^- 9 C

q2 = 8 x 1 x 10^- 9 C

F = (9 x 10^9 x 4 x 1 x 10^- 9 x 8 x 1 x 10^- 9)/0.04^2

F = 1.8 x 10^-4N

There is an attraction

For trial 3,

q1 = - 6μC

q2 = 8μC

q1 = - 6 x 1 x 10^- 9 C

q2 = 8 x 1 x 10^- 9 C

F = (9 x 10^9 x 6 x 1 x 10^- 9 x 8 x 1 x 10^- 9)/0.04^2

F = 2.7 x 10^-4N

There is an attraction

For trial 4,

q1 = - 8μC

q2 = 8μC

q1 = - 8 x 1 x 10^- 9 C

q2 = 8 x 1 x 10^- 9 C

F = (9 x 10^9 x 6 x 1 x 10^- 9 x 8 x 1 x 10^- 9)/0.04^2

F = 3.6 x 10^-4N

There is an attraction

The change in the value of the charge is proportional to the force