First, we multiply
[tex]\frac{-3}{5}\times17=\frac{-3\times17}{5}=\frac{-51}{5}[/tex]We can approximate -51/5 to -50/5, like this:
[tex]\frac{-51}{5}\approx\frac{-50}{5}\approx-10[/tex]Then:
[tex]\frac{-3}{5}\times17\approx-10[/tex]Now, with the second multiplication
[tex]-\frac{3}{5}\times\frac{5}{6}[/tex]As five appears multiplying in both the numerator and the denominator, we can cancel it
[tex]-\frac{3}{5}\times\frac{5}{6}=-\frac{3}{6}=-\frac{1}{2}[/tex]Since the half of 1 is 0.5 then:
[tex]-\frac{1}{2}=-0.5[/tex]Then:
[tex]-\frac{3}{5}\times\frac{5}{6}=-0.5[/tex]