Notice that the distance between the home plate to second base is the diagonal of a square:
From the Pythagorean Theorem, since a right triangle is formed by the diagonal and the two sides of the square, then the distance from home to the second base is:
[tex]\begin{gathered} d=^2\sqrt[]{(90ft)+(90ft)^2} \\ =\sqrt[]{2(90ft)^2} \\ =\sqrt[]{2}\times(90ft) \\ \approx127.3ft \end{gathered}[/tex]
