Subtract the rational expressionsAnswer in simplest for multiply any factors in the numerator and denominator Answers with variables in descending power and in alphabetical order

So here we have the rational expressions, which we're going to substract:
[tex]\frac{x-1}{x+1}-\frac{2x+3}{2x+1}[/tex]We're going to substract them as fractions:
[tex]\frac{(x-1)(2x+1)-(x+1)(2x+3)}{(x+1)(2x+1)}[/tex]And then distribute:
[tex]\begin{gathered} \frac{2x^2+x-2x-1-(2x^2+3x+2x+3)}{2x^2+3x+1} \\ \\ \frac{2x^2-x-1-2x^2-5x-3}{2x^2+3x+1} \\ \\ \frac{-6x-4}{2x^2+3x+1} \\ \end{gathered}[/tex]So that's the answer.
The numerator is -6x-4
The denominator is 2x^2+3x+1