In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
7x^2-16x-15
Step 02:
Quadratic Equation
[tex]x\text{ = }\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]ax² + bx + c = 0
= 0
a = 7
b = -16
c = -15
[tex]x\text{ = }\frac{-(-16)\pm\sqrt[]{(-16)^2-4\cdot(7)(-15)_{}}}{2(7)}[/tex][tex]\begin{gathered} x1=\text{ }\frac{16+26}{14}=3 \\ x2=\frac{16-26}{14}=\frac{-5}{7} \end{gathered}[/tex]The answer is:
7x² - 16x - 15 = (x - 3)(x + 5/7)
