Question

Light of two different wavelengths is used in a double-slit experiment. The location of the third order bright fringe for yellow-orange light (l= 576.4 nm) coincides with the location of the fourth order fringe for the other color's light. What is the wavelength, in nm, of the other light?

Answer 1

Given:

Wavelength of the third order bright fringe = 576.4 nm

Let's find the wavelength of the other light located in the fourth order fringe.

To find the wavelength, apply the formula:

$3\lambda_1=4\lambda_2$

Thus, we have:

$\begin{gathered} 3*576.4=4\lambda_2 \\ \\ \lambda_2=\frac{3*576.4}{4} \\ \\ \lambda_2=\frac{1729.2}{4} \\ \\ \lambda_2=432.3\text{ nm} \end{gathered}$

Therefore, the wavelength in nm of the other light is 432.3 nm.

ANSWER:

432.3 nm