Question

Knowledge regarding trapezoidal sum is required for solving this question.

Answer 1

Solution

Applying the Trapezoidal sum

$Sum=\frac{h}{2}(sum\text{ of first and last ordinates\rparen}+h(sum\text{ of other ordinates\rparen}$$Sum=\frac{b-a}{2}(f(a)+f(b))$$\begin{gathered} sum_1=\frac{2-0}{2}(7+4)=11 \\ \\ sum_2=\frac{5-2}{2}(3.2+4)=10.8 \\ \\ sum_3=\frac{7-5}{2}(3.2+2.2)=5.4 \\ \\ sum_4=\frac{11-7}{2}(2.2+1.6)=7.6 \\ \\ sum_5=\frac{12-11}{2}(1+1.6)=1.3 \end{gathered}$

Hence, Total Sum = 11 + 10.8 + 5.4 + 7.6 + 1.3 = 36.1

Hence, the total oil consumed is 36.1