Question

Find the product of (4z2 + 7z - 8) and (-z + 3).The product of (4z2 + 77 - 8) and (-Z + 3) is -423 +Z - 24.

Answer 1

The product of

$\begin{gathered} 4z^2+7z-8 \\ by \\ -z+3 \end{gathered}$

is

$(4z^2+7z-8)(-z+3)=4z^2\cdot(-z)+7z\cdot(-z)-8\cdot(-z)+4z^2\cdot3+7z\cdot3-8\cdot3$

doing the respective products, we have

$(4z^2+7z-8)(-z+3)=-4z^3-7z^2+8z+12z^2+21z-24$

by combining similar terms, we obtain

$(4z^2+7z-8)(-z+3)=-4z^3+5z^2+29z-24$