Respuesta :

GIVEN:

We are given two right triangles as indicated and these are;

[tex]\begin{gathered} \Delta ABY\text{ } \\ \\ \Delta YXZ \end{gathered}[/tex]

Required;

To find the ratio of the sides of the triangle ABY.

Step-by-step solution;

We shall take into consideration the values of the special angles as shown in the right triangles and these are as follows;

[tex]\begin{gathered} Angle\text{ }30\degree: \\ \\ sin30\degree=\frac{1}{2} \\ \\ cos30\degree=\frac{\sqrt{3}}{2} \\ \\ tan30\degree=\frac{1}{\sqrt{3}} \end{gathered}[/tex][tex]\begin{gathered} Angle\text{ }60\degree: \\ \\ sin60\degree=\frac{\sqrt{3}}{2} \\ \\ cos60\degree=\frac{1}{2} \\ \\ tan60\degree=\sqrt{3} \end{gathered}[/tex][tex]\begin{gathered} Angle\text{ }45\degree: \\ \\ sin45\degree=\frac{\sqrt{2}}{2} \\ \\ cos45\degree=\frac{\sqrt{2}}{2} \\ \\ tan45\degree=1 \end{gathered}[/tex]

Observe carefully that the line AB is also the OPPOSITE of angle 30 degrees. This means line AB can also take on the value 1

That is,

[tex]AB=1[/tex]

Then the line BY is the hypotenuse of triangle ABY and its length is 2.

That is;

[tex]BY=2[/tex]

Line YA is the ADJACENT of triangle ABY and its length is √2.

That is;

[tex]YA=\sqrt{2}[/tex]

These can be better illustrated as follows;

Therefore, from the side lengths derived as shown above, the ratio of the sides of triangle ABY is as follows;

[tex]1:2:\sqrt{2}[/tex]

ANSWER:

The fourth option is the correct answer.

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